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(b)an earthed conductor was brought near the charged student. a spark jumped between the conductor and the student. the potential

Question

(b)An earthed conductor was brought near the charged student. A spark jumped between the conductor and the student. The potential difference between the conductor and the student was 2.5 kV The energy transferred by the spark was 0 .0050 J Calculate the charge transferred by the spark. __ Charge =

Answer

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Verificación de expertos
Isaiah Master · Tutor for 5 years

Answer

The charge transferred by the spark equals to C.

Explanation

The relationship between energy (E), the electric potential difference (V), and charge (Q) can be represented as E = QV, hence Q could be calculated as Q = E/V; 1. First, we need to ensure that the units used in the calculation are compatible. The potential difference is given in kilovolts (kV), but the energy is in joules (J). In scientific units such as the Joule, the charge is typically represented in Coulombs (C). However, kilovolts should be converted to volts (V), where 1 kV = 1000 V, thus 2.5 kV = 2500 V.2. Substituting the given values into the equation Q = E/V gives Q = 0.005 J / 2500 V. Calculate this, and you'll get Q.3. Therefore, we need CMD the above division that prompt gives Q = 0.005 / 2500 = 2e-6 C to find the charge transferred.