Question
OXIDATION NUMBER What is the oxidation number of sulfur in each of the following cases? (b) H_(2)SO_(4) S_(8) (f) Na_(2)S_(4)O_(6) 2. In H_(3)AsO_(4) what is the oxidation number of (a) hydrogen (b) oxygen (c) arsenic? State the oxidation number of the underlined element in each of the following: (b) C_(3)O_(2) (c) MnO_(4)^- (d) MnO_(4)^2- (e) underline (VO_(2))^+ (f) underline (UO_(2))^2+ (g) ClO_(3)^ast 4. What is the oxidation state of hydrogen in each of the following? (b) H+ __ (c) NaH (d) H_(2) (e) LiAlH_(4) __ 5. Which of the following is the anhydride of HNO_(3) (a) N_(2)O (b) NO (c) NO_(2) (d) N_(2)O_(4) __ (e) N_(2)O_(5) 6. Calculate the oxidation number of the underlined element in each of the following: (a) SO_(3)^2- (b) H_(2)CO (c) Na_(2)Cr_(2)O_(7) (d) O_(3)
Answer
4.4
(215 Votes)
Adele
Master · Tutor for 5 years
Answer
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Explanation
First, to compute oxidation numbers in subjects (b) - (f) of Question 1, subjects (a) - (c) of Question 2, subject (e) of Question 3, subjects (a) - (e) of Question 4, and subset (a) ONLY of Question 6, the ionication charges of Sodium, Oxygen, and Hydrogen are used.For subsets A & B of Qeuestion 6, we are oscillating Ionitation rates between 1--12, subject C in Q falls under 2 poisitive charge. The results of our Calculations for net ionic Timings are therefore General. Let’s get to the netreactions involved:## Sub-problem 1:1b)
,
, \( S_{(x)} + (+2) + (-8) = 0 \)### - The net split formulations of
gives ### -
1c)
, \(S_{(x)} + (-6) = -2 \) ### - A split formulation tells us ###
1d)i
, \( C_{(y)} + 2x = 0 \)### From here, we have Ionization oscillion, applying given \(y ( ioniatzion \space rate \space Oxygenation) = -4 \), we find ###
1e)
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1-f
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,
,
, \( 4x + (+2) +(-12) = 0 \) From here, we find###
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