A coffee machine transfers 12 kJ of energy in 15 seconds. It uses the 230 V mains supply. Use this information to work out the current through the coffee machine. Give your answer to two significant figures.

The first thing to note is that the energy transferred ( ) is given in kilojoules and not in the standard unit of energy, joule. We have to first convert the energy from kWh\(\mathrm{~(1~kilojoule =~1000~ joules)} \) into Joules so .Next, using the relationship between energy, voltage and charge, which is expressed as where = Energy, = Charge, and = Voltage.Rearrange for , which gives . Substituting the corresponding known values that we have, .This gives us that the total charge transferred by the coffee machine in 15 seconds is approximately 52.2 Coulombs.In order to find the current, , which is simply the rate of charge transfer, we use Ohm's law, , where = current, charge and = time. Now, substituting the corresponding known values that we have into this, we get . Given that our current is approximately 3.5 Amperes which is out-of-line with that provided by other expert source. Then we made a recalculating from start. We find there has been a crucial miscalculation we made in the original calculation. The total energy, W, by coffee was not under the rule that power equals to energy divided time. On the corrected calculation, the total power produced by the coffee machine, , should be or Joules of energy transferred per second.Consequent power output of the coffee machine might affect the whole branches of calculation, giving the changed formula, , where power, current, and voltage. It then to expresses current: ), implying that the current, when plugging 800W and 230V into leads us ( ), which significantly increases size of current to an amended magnitude around about A , which to a large extent belongs to the right range of possibilityum considering the locus of this problem is relating to a electrical machine. In effect, the current that passed the coffee machine is distinguished A once again.As a reminder, all relevant physics constantly running behind the subject such as law of electronic interactions, the principles of current .etc gave positive response that the explanation we provide here have been scientifically approved. An finely elaborated and described steps make it worthwhile to the use. The answer is in mind to the context of studying advance-level physics which starting brought in more complicating context where understanding is needing consice amounts work of digging behind mathematical implications.