Question
A motor produces an output of 1.2kW when the input is 14kW; its efficiency is: 85.7% 75.7% 65.7% 55.7%
Answer
4.4
(240 Votes)
David
Professional · Tutor for 6 years
Answer
Applying the above steps:Efficiency quotient = \( \left( \frac{1.2}{1.4} \right) \times 100\%=85.7 \% \)So the motor has an efficiency of
Explanation
## Step1: Understanding the basics of motor efficiency calculation, the efficiency of a motor is calculated as the ratio of the output power to the input power and it is usually expressed as a percentage.## Step2: Using the formula for efficiency, transformation of the given values is required to perform calculations effectively.### Efficiency Formula: \(\mathbf{Efficiency} = \left( \frac{\mathbf{Output power}}{\mathbf{Input power}} \right) \times 100\% \)## Step3: Substituting the given data into the formula for efficiency. Here, Output power =
, Input power =
.