The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5 ,200J of energy to heat 2kg of it from 42^circ C to 47^circ C Enter your answer as a number J/kg^circ C C=(E)/(mtimes Theta )

The formula to calculate the specific heat capacity is given by , where:- is the amount of heat energy used in Joules (J).- is the mass of the substance in kilograms (kg).- is the specific heat capacity, which we are trying to find.- represents the change in temperature, measured in degrees Celsius (°C)In this particular problem, you are given that:- The energy, , used was 5200 Joules (J).- The substance's mass, , was 2 kg.- The change in temperature, , can be determined by subtracting the initial temperature from the final temperature, which is or 5 Kelvin (K), as Celsius and Kelvin have the same scale.We will rearrange our formula to solve for as highlighted in the below step by step:Re-arrange formula:\( c = Q / (m \cdot \Delta T) \)Solve with given values:\( c = 5200 \mathrm{~J} / (2 \mathrm{~kg} \cdot 5 \mathrm{~K}) = 520 \mathrm{~J/kg~K} \)Your calculated answer ~~Thus, yes, the specific heat capacity of the substance is .