Question
Algebra - Clark Two Variable Inequalities -Standard Form 2012 Kuta Software LLC. All rights reserved. Sketch the graph of each linear inequality. 1) 6x-ygeqslant -5 a 3 a -6 -5 -4 -3 -2 -1 0 -6
Answer
4.2
(190 Votes)
Magnus
Master · Tutor for 5 years
Answer
Step 1: Rewrite the inequality in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. 6x - y ≥ -5=> y ≤ 6x + 5Step 2: Draw the line y = 6x + 5. Since the inequality is 'less than or equal to', the line should be solid to indicate that points on the line are included in the solution.Step 3: Choose a test point not on the line to determine which side of the line is part of the solution to the inequality. A good test point is the origin (0,0) if it's not on the line.Substitute (0,0) into the inequality:0 ≤ 6*0 + 50 ≤ 5Since this is true, the area of the graph that includes the origin is part of the solution.Step 4: Shade the area of the graph that includes the origin. This shaded area represents all the points (x,y) that make the inequality true.