Select the correct answer from each drop-down menu. A reaction proceeds with 272 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reaction Mg(ClO_(3))_(2)+2NaOH-Mg(OH)_(2)+2NaClO_(3) Determine the theoretical amount of each product that the reaction will produce. The reaction will produce square of magnesium hydroxide and square of sodium chlorate.

Question

Select the correct answer from each drop-down menu. A reaction proceeds with 272 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reaction Mg(ClO_(3))_(2)+2NaOH-Mg(OH)_(2)+2NaClO_(3) Determine the theoretical amount of each product that the reaction will produce. The reaction will produce square of magnesium hydroxide and square of sodium chlorate.

Answer 1

The reaction will produce 2.72 moles of magnesium hydroxide and 5.44 moles of sodium chlorate.

Answer 2

To determine the theoretical amount of each product, we need to use stoichiometry. The balanced equation shows that 1 mole of magnesium chlorate reacts with 2 moles of sodium hydroxide to produce 1 mole of magnesium hydroxide and 2 moles of sodium chlorate. We use the limiting reagent (magnesium chlorate) to calculate the products.

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