The initial temperature of the mixture was +20^circ C The mixture froze at -1.5^circ C A total of 165 kJ of internal energy was transferred from the mixture to cool and freeze it. specific heat capacity of the mixture=3500J/kg^circ C specific latent heat of fusion of the mixture=255000J/kg Calculate the mass of the mixture. Give your answer to 2 significant figures. [6 mark

## Step 1: First, we need to calculate the energy used to cool the mixture from to . This can be calculated using the formula:### where is the heat energy, is the mass, is the specific heat capacity, and is the change in temperature.## Step 2:Substitute the given values into the formula:### \(Q = m \times 3500 \times (20 - 0)\)## Step 3:Rearrange the equation to solve for :### ## Step 4:The total energy transferred is 165 kJ, which is equal to . The energy used to cool the mixture to is subtracted from the total energy to find the energy used to freeze the mixture.### ## Step 5:The mass of the mixture can then be calculated using the formula:### where is the specific latent heat of fusion.## Step 6:Substitute the given values into the formula:### ## Step 7:Solve the equation to find the mass of the mixture.