Question
The velocity-time graph for a cycle is shown. a) Work out the distance travelled on the cycle in the first 14 seconds. b) Work out the acceleration in the first 4 seconds.
Answer
4.2
(249 Votes)
Quentin
Master · Tutor for 5 years
Answer
a) The distance travelled in the first 14 seconds is given by the formula
. Without the specific values from the graph, I can't provide a numerical answer.b) The acceleration in the first 4 seconds is given by the formula
. Without the specific values from the graph, I can't provide a numerical answer.
Explanation
## Step 1: Understanding the problemThe problem involves two parts: calculating the distance travelled in the first 14 seconds and calculating the acceleration in the first 4 seconds. Both of these calculations involve understanding the concepts of velocity, time, distance, and acceleration. ## Step 2: Calculating the distance travelled in the first 14 secondsThe distance travelled by an object is the area under the velocity-time graph. In the first 14 seconds, the graph is a triangle. The area of a triangle is given by the formula
.### Formula:
## Step 3: Calculating the acceleration in the first 4 secondsAcceleration is the rate of change of velocity with respect to time. It can be calculated from the slope of the velocity-time graph. In the first 4 seconds, the graph is a straight line, so the acceleration is constant. The slope of a line is given by the formula
, where y represents velocity and x represents time.### Formula: