,What mass of tron is formed when 240 g of iron(III) oxide reacts with carbon monoxide? Fe_(2)O_(3)+3COarrow 2Fe+3CO_(2) 2 What mass of oxygen reacts with 9.2 g of sodium? 4Na+O_(2)arrow 2Na_(2)O

Question 1: What mass of iron is formed when 240 g of iron(III) oxide reacts with carbon monoxide?【Explanation】: The balanced chemical reaction provided is \(\text{Fe}_{2}\text{O}_{3}+(3\text{CO})→2\text{Fe}+3\text{CO}_2\). According to stoichiometry of this reaction, one mole of forms two moles of Fe upon reaction with CO. Let's proceed in the following steps:1. First, we need to calculate the molar mass of Fe2O3. This comprises 2 moles of iron (Fe with a relative atomic mass of approximately 55.85 u), and 3 moles of oxygen (O, having atomic mass roughly 16.00 u). So, its molar mass will be \((2 \times 55.85) + (3 \times 16) = 159.7 \, \text{g} / \text{mole}\).2. Having the molar mass, we can compute the number of moles in the provided 240.0 grams of Fe2O3. By using the formula: \(\text{Mole}`) = ( \text{ Given Mass} ) / ( \text{Molar mass}\), we get of Fe2O3.3. Based on the reactions stoichiometry, 2 moles of Fe are produced by one mole of Fe2O3. Hence, 1.50 moles of Fe2O3 will create 3.0 moles of Fe.4. Now we can compute the mass of these 3.0 moles of Fe. As molar mass of iron(Fe) is 55.85, by multiplying the no of moles with molar mass we get, .【Highlight Answer】: So the mass of iron formed when 240 g of iron(III) oxide reacts with carbon monoxide will be approximately 167.55 g.Question 2: What mass of oxygen reacts with 9.2 g of sodium?【Explanation】: The balanced chemical reaction indicates that 4 moles of Sodium reacts with 1 mole of Oxygen to form 2 moles of Sodium Oxide ( ). To find out the mass of Oxygen that reacts with 9.2g of Sodium we can proceed in the following steps:1. Calculate the number of moles of sodium in the given 9.2 grams, using the relationship: Moles = ( mass/molar mass) with the molar mass of Sodium being approximately 22.99 g/mole. The moles will be .2. As per the balanced chemical equation, 4 mole of Sodium (Na) reacts with 1 mole of Oxygen ( ). Hence, 0.400 moles of Na will react with of Oxygen.3. Finally calculate the mass of 0.100 moles of Oxygen using the formula Mass = ( No. of moles) x ( Molar mass), Considering molecular oxygen we have: O_{2}\)) = 3.20 \, \text{g}\).【Highlight Answer】: Therefore, the mass of oxygen that reacts completely with 9.2 g of sodium will be around 3.20 g.