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which lunction describes the graph below? f(x)=6cos(x) f(x)=3cos(x)+3 f(x)=6sin(x)

Question

Which lunction describes the graph below? f(x)=6cos(x) f(x)=3cos(x)+3 f(x)=6sin(x)

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Roger Professional · Tutor for 6 years

Answer

To determine which function describes the graph, we need to consider the characteristics of the cosine and sine functions and how they are transformed by different coefficients and constants.Let's analyze the given functions and the details of the graph:1. \(f(x) = 6 \cos(x)\)The basic cosine function, \(\cos(x)\), starts at a maximum point when . The coefficient 6 would stretch the graph vertically by a factor of 6. This means the maximum value of \(f(x)\) would be 6 when , which matches the point (0,6) on the graph. However, the basic cosine function decreases after , which does not match the initial increase in the graph.2. \(f(x) = 3 \cos(x) + 3\)This function is a vertically stretched cosine function with a vertical shift upwards by 3 units. The basic cosine function starts at a maximum, and with the vertical shift, the starting point would be at \(f(0) = 3 \cos(0) + 3 = 3(1) + 3 = 6\), which matches the point (0,6). However, we need to check if the rest of the graph matches the given points.The cosine function has a period of , and it reaches its first zero at in the basic form. However, without a horizontal scaling factor, the function \(3 \cos(x) + 3\) would not have zeros at and because these values do not correspond to or (the points where the basic cosine function crosses the x-axis).3. \(f(x) = 6 \sin(x)\)The basic sine function, \(\sin(x)\), starts at with a value of 0 and then increases. The coefficient 6 would stretch the graph vertically by a factor of 6. The sine function reaches its first zero at , which is approximately 3.14159. This does not match the zeros at and given in the graph.Given the points and the shape of the graph, none of the provided functions seem to perfectly match the description of the graph. The graph increases from (0,6), which would suggest a sine-like starting behavior, but the sine function does not have zeros at the points (1.5,0) and (4.5,0). The cosine functions provided do not match the behavior of the graph either, as they do not start with an increasing trend from (0,6).Therefore, based on the information provided and the standard forms of sine and cosine functions, none of the given options \(f(x) = 6 \cos(x)\), \(f(x) = 3 \cos(x) + 3\), or \(f(x) = 6 \sin(x)\) correctly describe the graph with the specified points and shape. There may be an error in the question or the provided options, or additional transformations (such as horizontal shifts or stretches) may be required to match the graph.