Solving these equations 125 - 4q1 = 100 - 6q2 = 6Q + 5

## SolutionThe given equations are:```125 - 4q1 = 100 - 6q2 = 6Q + 5```This is a system of three equations. To solve it, we can break it down into two separate equations:1. 125 - 4q1 = 6Q + 52. 100 - 6q2 = 6Q + 5Let's solve each equation separately.### Equation 1: 125 - 4q1 = 6Q + 5To isolate `q1`, we can rearrange the equation as follows:```4q1 = 125 - 6Q - 5```Then, divide both sides by 4 to solve for `q1`:```q1 = (125 - 6Q - 5) / 4```### Equation 2: 100 - 6q2 = 6Q + 5Similarly, to isolate `q2`, we can rearrange the equation as follows:```6q2 = 100 - 6Q - 5```Then, divide both sides by 6 to solve for `q2`:```q2 = (100 - 6Q - 5) / 6```Now, you have `q1` and `q2` in terms of `Q`. To find the specific values, you would need additional information or constraints on `Q`.Please note that the solution might vary depending on the context of the problem. If `Q`, `q1`, and `q2` are related in a specific way, you might need to use that relationship to find the solution.