6. Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (table sugar) when dissolved in water. It is marketed by G.D. Searle as Nutro Sweet. The molecular formula of aspartame is C_(14)H_(18)N_(2)O_(5) a) Calculate the molar mass of aspartame. b) How many moles are in 15.0 g of aspartamei c) What is the mass in grams of 1.56 moles of aspartame? d) How many molecules are in 5000. g of aspartame? many molecules carbon dioxide CO_(2) are in 6.53 liters of carbon dioxide?

Question

6. Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (table sugar) when dissolved in water. It is marketed by G.D. Searle as Nutro Sweet. The molecular formula of aspartame is C_(14)H_(18)N_(2)O_(5) a) Calculate the molar mass of aspartame. b) How many moles are in 15.0 g of aspartamei c) What is the mass in grams of 1.56 moles of aspartame? d) How many molecules are in 5000. g of aspartame? many molecules carbon dioxide CO_(2) are in 6.53 liters of carbon dioxide?

Answer 1

To solve these problems, keep in mind the basic conversions one needs to understand in chemistry: molar mass, moles to grams conversions, and the relationship between moles and molecules represented by Avogadro's number.Question 6:a) To calculate the molar mass of aspartame, identify and sum the product of the counts of all atoms and their respective atomic masses. By looking to the periodic table, the average atomic masses for Carbon (C), Hydrogen (H), Nitrogen (N) and Oxygen (O) can be approximated: C = 12.01g/mol, H = 1.007g/mol, N = 14.01g/mol and O = 16.00g/mol. So the formula to do this is:Molar mass = 14(C) + 18(H) + 2(N) + 5(O). The molar mass of Aspartame is approximately 294.3 g/mol in total.b) The number of moles in 15.0 g Aspartame refers to Avogadro's principle of molar mass: the grams of a substance divided by its molar mass results in the amount of moles of that substance, therefore:Moles = 15.0 g / 294.3 g/mol which equals approx. 0.051 mol.c) To work this out reverse the calculation in part b aka: mass = moles x molar mass which equals: 1.56 mol Aspartame * 294.3 g/mol = 458.90g -> Approx. 459g of Aspartame.d) Formula for this is: Moles = 5000g Aspartame / 294.3 g/mol which amount to approx. 16.99 mol Aspartame. Subsequently calculate the molecules by adding Avogadro's number: 16.99 mol * Avogadro's number (6.022 x 10^23 molecules/mol). Ultimately we gain ~ 1.02 x 10^25 molecules of Aspartame.Question 7:Assuming carbon dioxide occupies 22.4 litres per mol at standard temperature pressure (STP 0 °C, 101kPa), you can derive how many CO_2 molecules in 6.53 litres use this First Calculation: Moles CO2 = Volume (L) / Volume of 1 mol at STP (L/mol)= 6.53 L / 22.4 L/mol = 0.291 molesSecond calculation, plug in Avogadro's number:= 0.291 mol * Avogadro's number (6.022 x 10^23 molecules/mol).= ~ 1.75 x 10^23 CO_2 molecules. 【Answer】: a. The molar mass of aspartame is approx. 294.3 g/mol. b. There are approx. 0.051 moles in 15 g of Asparteme. c. The mass of 1.56 moles of aspartame is approx. 459 g. d. There are about 1.02 x 10^25 molecules in 5000 g of aspartame.e. There are approx. 1.75 x 10^23 CO_2 molecules in 6.53 litres of CO_2.