The equation for the formation of hydrochloric acid is shown below. Calculate the energy released by forming bonds in this reaction . Use the table to help you. Enter a number kJ/mol H_(2)+Cl_(2)arrow 2HCl Bond Bond energy (kJ/mol) H-H 436 O=O 498 H-O 464 C-H 413 C=O 803 Nequiv N 945 N-H 391 Cl-Cl 243 H-Cl 432

## Step 1: Identify the bonds formed in the reaction### In the formation of hydrochloric acid (HCl), the reaction involves the formation of H-Cl bonds.## Step 2: Determine the bond energy for H-Cl### According to the given table, the bond energy for one H-Cl bond is 432 kJ/mol.## Step 3: Calculate the total bond energy for the products### Since the reaction produces 2 molecules of HCl, we need to multiply the bond energy of one H-Cl bond by 2.### #