Question
Balance the Equation by adding in the correct coefficients. (If you wouldn't change the coefficient for the particular molecule then its value would be "1") Na_(2)SO_(3)+ldots S... ... ... Na_(2)S_(2)O_(3) 1,1,1 2,2,3 1,2,3
Answer
4.4
(205 Votes)
Lorraine
Professional · Tutor for 6 years
Answer
1, 2, 1.
Explanation
In balancing a chemical equation, the aim is to ensure equal numbers of each kind of atom present in the reactant side and those on the product side of the equation: Balancing starts by inspection, comparison, and adjustment, principles akin to trial-and-error. Observing `Na2SO3` and unraveling presents us with Sodium numbering `2`, Sulfur `1`, and Oxygen `3` atoms. `S` reveals `1` Sulfur atom and `Na2S2O3` comes across with Sodium giving `2`, Sulfur `2`, and Oxygen implying `3` atoms respectively. From what we've unmasked, we can see that Sulfur and Oxygen atoms are not balanced. Hence, a route to balancing the proportion stating by adjusting the values associated with `S`, we could take coefficient `2` for `S` by the motive of clearing the path of Sulfur values balance between the left and right sides via associating each atom type in common compared in the reaction formula, the ways through for resolving emerged. No further delay, taking Oxygen into account must follow concurrently with due assignment post-Sulfur confrontation and we are not dismayed since keeping `1` as the coefficient Permit Sodium, Oxygen, and Sulfur atoms comply stroked. For this reason upon the final read view, rational combing confronts element-wise, announces form for passage product on structured building with unity. Standing tight, however, prompts writing (typically) an equation given after supremacy battle on both extremist parts equals as ensues: Mending with `1Na2SO3(s)`+`2S(s)`→`Na2S2O3(s)`. Trigger by the agency of reframed knowledge gain frames gives the best coefficients offering winning margin solution broad, setting step reached the edge.