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485=tens+5units 2(1)/(2)kg=g 2000+900+70+6= 25cm=mm 9000div 10= f1.00-82p=p 37div 4= p-8p=5p 3103+97= write 44 using roman numerals.

Question

485=tens+5units 2(1)/(2)kg=g 2000+900+70+6= 25cm=mm 9000div 10= f1.00-82p=p 37div 4= p-8p=5p 3103+97= Write 44 using Roman numerals. 1l-350ml=ml (9times 9)+8=

Answer

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Answer

1. 480 tens2. 2500 grams3. 29764. 250 mm5. 900 6. 18 pence7. remainder 18. p = 09. 320010. XLIV11. 760 ml 12. 89

Explanation

This question consists of several sub-questions regarding different aspects of numeracy. Each sub-question requires a numerical calculation or conversion: 1. 485=tens+5 → There are 48 tens and 5 units (ones) in the number 485. 2. 2.5 kg=g → To convert kilograms to grams, multiply by 1000 because there are 1000 grams in a kilogram.3. 2000+900+70+6 = ### → Simple addition is required to get the sum of these numbers. 4. 25 cm= mm → To convert centimetres to millimetres, multiply by 10. 5. 9000 ÷ 10= ### → Division is the required mathematical operation here.6. £1.00––82p=p → Converting pounds to pence (100 pence in a pound) and subtracting 82 pence.7. 37 ÷ 4= r → Performing a division operation and reporting the remainder (when 37 is divided by 4) as r.8. p––8p=5p → An algebraic question, we need to find the value of p which makes this equation hold true.9. 3103+97=### → Simple addition is necessary to get the sum of these numbers.10. Writing 44 using Roman numerals → Requires understanding of how to represent numbers on the Roman numeral system. In this system: "X" = 10, "XX" = 20, "XXX" = 30, "L" = 50; therefore, 40 is "XL" being "L - X = 40". Then, we just add “IV” which is 4 ("V" = 5, and "V - I = IV = 4").11. 1110-350 → Subtracting 350 milliliters from 1110 milliliters.12. (9 × 9) + 8 → This is do calculation with parentheses first (9 × 9), then add 8 to the result.