7 Calculate the relative formula mass of methanol, CH_(3)OH A_(r) values: C=12,O=16,H=1

The relative formula mass of a molecule is the sum of the relative atomic masses of the atoms in its formula.In the case of methanol, it consists of Carbon (C), Hydrogen (H), and Oxygen (O).From the question, the given relative atomic masses values are: Carbon (C) = 12,Oxygen (O) = 16,Hydrogen (H) = 1Calculating the relative formula mass we consider each atom in the molecule and multiply it by its quantity and then sum up the total. Methanol (CH3OH) consists of 1 atom of Carbon, 4 atoms of Hydrogen and 1 atom of Oxygen. Therefore the relative formula mass of methanol (CH3OH) will be\(= 1(C) + 4(H) + 1(O)\)\(= 1(12 u) + 4(1 u) + 1(16 u)\)