Question
(e) The acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 The velocity of the apple changes from 0 to 4.9 mathrm(~m) / mathrm(s) Calculate the time taken for the apple to fall to the ground. Use the equation: [ (1+4.4)/(9.8)=0,5 ]
Answer
4.7
(203 Votes)
Charlotte
Master · Tutor for 5 years
Answer
The time taken for the apple to fall to the ground is approximately
seconds.
Explanation
## Step1:First, we identify the given values from the problem. The initial velocity (vi) of the apple is 0 m/s, the final velocity (vf) is 4.9 m/s, and the acceleration (a) is 9.8 m/s².## Step2:We use the given formula to calculate the time taken for the apple to fall to the ground. The formula is:###
The change in velocity is the final velocity minus the initial velocity. In this case, it is 4.9 m/s - 0 m/s = 4.9 m/s.## Step3:Substituting the values into the formula, we get:###