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(e) the acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 the velocity of the apple changes from 0 to 4.9 mathrm(~m) /

Question

(e) The acceleration of the apple is 9.8 mathrm(~m) / mathrm(s)^2 The velocity of the apple changes from 0 to 4.9 mathrm(~m) / mathrm(s) Calculate the time taken for the apple to fall to the ground. Use the equation: [ (1+4.4)/(9.8)=0,5 ]

Answer

4.7 (203 Votes)
Verificación de expertos
Charlotte Master · Tutor for 5 years

Answer

The time taken for the apple to fall to the ground is approximately seconds.

Explanation

## Step1:First, we identify the given values from the problem. The initial velocity (vi) of the apple is 0 m/s, the final velocity (vf) is 4.9 m/s, and the acceleration (a) is 9.8 m/s².## Step2:We use the given formula to calculate the time taken for the apple to fall to the ground. The formula is:### The change in velocity is the final velocity minus the initial velocity. In this case, it is 4.9 m/s - 0 m/s = 4.9 m/s.## Step3:Substituting the values into the formula, we get:###