Question
A firework rocket starts from rest at ground level and moves vertically. In the first 3s of its motion, the rocket rises 27 m . The rocket is modelled as a particle moving with constant acceleration 6ms^-2 Find the speed of the rocket 3 s after it has left the ground.
Answer
4.1
(209 Votes)
Xavier
Professional · Tutor for 6 years
Answer
Using the provided values in the equation,
, we obtain \(v = 0 + (6 m/s² * 3 s) = 18 m/s\), which is the speed of the rocket 3 seconds after leaving the ground.
Explanation
## Step1: The problem is looking to find the speed of the rocket 3 seconds from the launch.In this case the initial speed (
) is 0 m/s, as mentioned in the problem, the rocket starts from rest. The time (
) is taken as 3 seconds and the acceleration (
) is given to be 6 m/s². We are not utilizing the distance in this problem to solve for requested speed; it is surplus information for this enquiry.## Step2. Apply the first law of motion to find the speed at 3 seconds,
.