(1)Vectors defer from scalars , because (A)direction of scalars must he considered together with the magnitude, (B)direction of vectors must be considered in computing its magnitude direction of scalars can he represented with arrow-headed I lines,(D)because direction of vectors are following methods can be used to add or resolve vectors except:(10parallelogram nule (B)triangle rule,(C)rectangle rule,(D)method of Pythagoras.(3)II'a body in motion or at rest is in equilibrium,it means that (A)All the forces acting on it is equivalent to zero force(B)All the forces acting on it has a resultant(C)The resultant of all the forces closes the triangle when drawn head to tail(D)The resultant of all the forces closes the rectangle when drawn head to tail (4) Statics of particle defers from that of the rigid body in the following ways except :(A)Forces acting at a point are studied and the shape of the body is neglected(B)Moments are not considered in particle statics(C)The r rigid body y is treated as a combination of several particles(D)The forces and their turning effects are considered in rigid body statics (5)A force of 50N and 70N acts on a hook as shown in Fig. I, the correct triangle of force for the resultant is: (6) The resultant of the 70kN C forces in Figl of Question 5 is:(A)20.85K N 50kN D (B) 30.5 KN(C)40.81KN (D) 10025KN (7)A force 50kN 70kN A & B F shown in Fig. 2 can be resolved as in x- axis (A)F cos 0 (B)F sin 6 Fig 1 (C)F tan 6(D)F cot e (8)The support of the Engineering structure shown in Fig. 3 is called and it has the following reactions: Ay, Ax and M_(A) (A) Cantilever; 10KN.OKN and 50KNM (B)Fixed support; 10KN, OK N and 50KN (C) Cantilever; 50KNM 10KN, OKN (D) Ilinged support: 50KNM, x 10KN and OKN (9)The simple beam shown in l'ig 4.0 has the Fig5 following constraints As, A and B,(A)2SKN, 50 KN and 25KN (B)26K N Fig 2 60 and 25KN 50KN and 30KN JOOKN (D)60KN, 100KN and 50KN (10)For the simple beam shown in fig 5. find the reactions at the supports: A, A, and B. :(A)OKN , 6KN and 60 AKN (B)OKN. 4KN and 6K N (C)6KN, OKN and A B 4KN (D)4KN , 6KN and OKN(11)Fig_6 is a joint in a truss, calculate the value of the member force FAD(A ).OKN(B).8KN (C)9.OKN (D)-9.0KM (12)In lig 6, what is the value of the force sm FAB(A)12.52KN(B)-12.52KN(C)14.42KN(D)-14.42KN Fig 7.0 shows a gable roof truss, well numbered in bow's notations and a corresponding Maxwell's Cremona force diagram drawn. The scale of the force diagram is i.C. the length of the lines in centimeter represents the forces in Kiloncwtons. Use Pythagoras theorem where necessary and answer question 13-19 (13)The reaction at support (B):10KN/C)/2KN/DH+12KN(14)The reaction at support B is:(A)8KN(B 4.42KN(D)-14.42KN(15)The force in member AD is compression (B)9KN. compression(C)BKN.Tension (D)9KN, tension(16)The force in member DC is: (A)8K N. tension(B)9KN. compression(C)8KN, compression(D)9KN. tension(17)What is the force in member BD?(A)20KN,tension(B)20KN. compression (C)40KN, tension(D)40KN. 12cr compression(18)The force in member AB is(A)14.42kN, compression(B) 4442kV, tension(C)R.0kN tension(D)9.0kN Fig 6 (A)It is the study of the condition of rest of bodies acted upon by forces.(B)It studies the condition of equilibrium of stationary bodies acted upon by forces (c)It studies the condition of equilibrium of bodies acted upon by forces but moving with uniform velocity(D)All of the above (21) A mathematical expression possessing both magnitude and direction and added according to law is called(A)Scalars (B)Vectors (C) Quantities (D) All of the above(22) A force is given as F=250i+354j-250k what is its magnitu (B) 700 (C) 900 (D)1000 (23) lfa vector makes the following angles 73.49,116.4 and makes the following angles 31.0^circ withx. 0.860i+0.439j+0.781k 5)0.8601+0.43i-0.78ik(D)0.100i+2.404i-0.900k 500.860i+u_(2)+12i(O)50i+150i-45(8)5O_(1)+250j-55kF50kC (C) 10i+ P_(1)(20.0,60,100),P_(2)(40,130,150) express this force in space co 12.04i+60.72j+70k 60i+80j+10k(26) A vector makes the following angles x=40^circ ,y=70^circ and y axis,respectively; what angles does it E_(1)=20i+50i+10K,F_(2)=70i+10j-30k and F_(3)=xi+yi+zk are

Question

(1)Vectors defer from scalars , because (A)direction of scalars must he considered together with the magnitude, (B)direction of vectors must be considered in computing its magnitude direction of scalars can he represented with arrow-headed I lines,(D)because direction of vectors are following methods can be used to add or resolve vectors except:(10parallelogram nule (B)triangle rule,(C)rectangle rule,(D)method of Pythagoras.(3)II'a body in motion or at rest is in equilibrium,it means that (A)All the forces acting on it is equivalent to zero force(B)All the forces acting on it has a resultant(C)The resultant of all the forces closes the triangle when drawn head to tail(D)The resultant of all the forces closes the rectangle when drawn head to tail (4) Statics of particle defers from that of the rigid body in the following ways except :(A)Forces acting at a point are studied and the shape of the body is neglected(B)Moments are not considered in particle statics(C)The r rigid body y is treated as a combination of several particles(D)The forces and their turning effects are considered in rigid body statics (5)A force of 50N and 70N acts on a hook as shown in Fig. I, the correct triangle of force for the resultant is: (6) The resultant of the 70kN C forces in Figl of Question 5 is:(A)20.85K N 50kN D (B) 30.5 KN(C)40.81KN (D) 10025KN (7)A force 50kN 70kN A & B F shown in Fig. 2 can be resolved as in x- axis (A)F cos 0 (B)F sin 6 Fig 1 (C)F tan 6(D)F cot e (8)The support of the Engineering structure shown in Fig. 3 is called and it has the following reactions: Ay, Ax and M_(A) (A) Cantilever; 10KN.OKN and 50KNM (B)Fixed support; 10KN, OK N and 50KN (C) Cantilever; 50KNM 10KN, OKN (D) Ilinged support: 50KNM, x 10KN and OKN (9)The simple beam shown in l'ig 4.0 has the Fig5 following constraints As, A and B,(A)2SKN, 50 KN and 25KN (B)26K N Fig 2 60 and 25KN 50KN and 30KN JOOKN (D)60KN, 100KN and 50KN (10)For the simple beam shown in fig 5. find the reactions at the supports: A, A, and B. :(A)OKN , 6KN and 60 AKN (B)OKN. 4KN and 6K N (C)6KN, OKN and A B 4KN (D)4KN , 6KN and OKN(11)Fig_6 is a joint in a truss, calculate the value of the member force FAD(A ).OKN(B).8KN (C)9.OKN (D)-9.0KM (12)In lig 6, what is the value of the force sm FAB(A)12.52KN(B)-12.52KN(C)14.42KN(D)-14.42KN Fig 7.0 shows a gable roof truss, well numbered in bow's notations and a corresponding Maxwell's Cremona force diagram drawn. The scale of the force diagram is i.C. the length of the lines in centimeter represents the forces in Kiloncwtons. Use Pythagoras theorem where necessary and answer question 13-19 (13)The reaction at support (B):10KN/C)/2KN/DH+12KN(14)The reaction at support B is:(A)8KN(B 4.42KN(D)-14.42KN(15)The force in member AD is compression (B)9KN. compression(C)BKN.Tension (D)9KN, tension(16)The force in member DC is: (A)8K N. tension(B)9KN. compression(C)8KN, compression(D)9KN. tension(17)What is the force in member BD?(A)20KN,tension(B)20KN. compression (C)40KN, tension(D)40KN. 12cr compression(18)The force in member AB is(A)14.42kN, compression(B) 4442kV, tension(C)R.0kN tension(D)9.0kN Fig 6 (A)It is the study of the condition of rest of bodies acted upon by forces.(B)It studies the condition of equilibrium of stationary bodies acted upon by forces (c)It studies the condition of equilibrium of bodies acted upon by forces but moving with uniform velocity(D)All of the above (21) A mathematical expression possessing both magnitude and direction and added according to law is called(A)Scalars (B)Vectors (C) Quantities (D) All of the above(22) A force is given as F=250i+354j-250k what is its magnitu (B) 700 (C) 900 (D)1000 (23) lfa vector makes the following angles 73.49,116.4 and makes the following angles 31.0^circ withx. 0.860i+0.439j+0.781k 5)0.8601+0.43i-0.78ik(D)0.100i+2.404i-0.900k 500.860i+u_(2)+12i(O)50i+150i-45(8)5O_(1)+250j-55kF50kC (C) 10i+ P_(1)(20.0,60,100),P_(2)(40,130,150) express this force in space co 12.04i+60.72j+70k 60i+80j+10k(26) A vector makes the following angles x=40^circ ,y=70^circ and y axis,respectively; what angles does it E_(1)=20i+50i+10K,F_(2)=70i+10j-30k and F_(3)=xi+yi+zk are

Answer 1

1. B2. D3. A4. C5. Unable to answer without the figure6. Unable to answer without the figure7. A8. Unable to answer without the figure9. Unable to answer without the question10. Unable to answer without the figure11. Unable to answer without the figure12. Unable to answer without the figure13. Unable to answer without the figure14. Unable to answer without the figure15. Unable to answer without the figure16. Unable to answer without the figure17. Unable to answer without the figure18. Unable to answer without the figure19. Unable to answer without the figure20. D21. D22. A23. Unable to answer without the angles

Answer 2

## Step 1: For question 1, vectors differ from scalars because the direction of vectors must be considered in computing its magnitude. Scalars only have magnitude and no direction.## Step 2: For question 2, the method of Pythagoras is not used to add or resolve vectors. The Pythagorean theorem is used in right triangles to find the length of the sides, not for vector addition or resolution.## Step 3: For question 3, if a body in motion or at rest is in equilibrium, it means that all the forces acting on it is equivalent to zero force. Equilibrium is a state in which net force and net torque on an object are both zero.## Step 4: For question 4, the statement that is not a difference between statics of a particle and that of a rigid body is that the rigid body is treated as a combination of several particles. This is a similarity, not a difference.## Step 5: For question 5, without the figure, it's impossible to determine the correct triangle of force for the resultant.## Step 6: For question 6, without the figure, it's impossible to determine the resultant of the forces.## Step 7: For question 7, a force F shown in Fig 2 can be resolved as in x- axis as

. ## Step 8: For question 8, without the figure, it's impossible to determine the support of the Engineering structure.## Step 9: For question 9, without the question, it's impossible to provide an answer.## Step 10: For question 10, without the figure, it's impossible to determine the value of the member force FAd.## Step 11: For question 11, without the figure, it's impossible to determine the value of the force FAB.## Step 12: For question 12, without the figure, it's impossible to provide an answer.## Step 13: For question 13, without the figure, it's impossible to provide an answer.## Step 14: For question 14, without the figure, it's impossible to provide an answer.## Step 15: For question 15, without the figure, it's impossible to provide an answer.## Step 16: For question 16, without the figure, it's impossible to provide an answer.## Step 17: For question 17, without the figure, it's impossible to provide an answer.## Step 18: For question 18, without the figure, it's impossible to provide an answer.## Step 19: For question 19, without the figure, it's impossible to provide an answer.## Step 20: For question 20, all of the statements are true of statics. It is the study of the condition of rest of bodies acted upon by forces, it studies the condition of equilibrium of stationary bodies acted upon by forces, and it studies the condition of equilibrium of bodies acted upon by forces but moving with uniform velocity.## Step 21: For question 21, a quantity that has both magnitude and direction and added according to parallelogram law is called a vector.## Step 22: For question 22, the magnitude of a force given as

is calculated using the formula ### \(F = \sqrt{(250^2 + 354^2 + (-250)^2)}\)which gives approximately 500.## Step 23: For question 23, without the angles, it's impossible to calculate the unit vector.

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