Last Answered 9/6/24 Complete the following equation for the IONISATION of sodium hydroxide in water.[Pay attention to both the STATE 5YMBOLS and the CHARGES in 5UPERSCRIPT] NaOH(s)arrow Na^+(aq)+OH^-(aq) NaOH(s)arrow Na^-(aq)+OH^+(aq) NaOH(s)arrow Na^+(s)+OH^-(s) NaOH(s)arrow Na^-(s)+OH^+(s)

## Step 1:Sodium hydroxide (NaOH) is a strong base, which means it dissociates completely in water. In this process, sodium hydroxide splits into sodium ions (Na^+) and hydroxide ions (OH^-).## Step 2:We need to pay attention to both the state symbols and the charges in superscript. When NaOH dissociates in water, the sodium ion (Na^+) and hydroxide ion (OH^-) are both in aqueous form (aq).## Step 3:We can represent this dissociation with the balanced chemical equation: ## Step 4:Looking at the given options, we see that the correct representation of this dissociation is: