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13. oacb is a parallelogram. overrightarrow (oa)=a and overrightarrow (ob)=b the points m, s n and t divide ob, bc, ca and ao in the

Question

13. OACB is a parallelogram. overrightarrow (OA)=a and overrightarrow (OB)=b The points M, S N and T divide OB, BC, CA and AO in the ratio 1:4 respectively. The lines ST and MN intersect at the point D. (a) Express overrightarrow (MN) n terms of a and b. (b) Express overrightarrow (ST) in terms of a and b. (c) Show that the lines MN and ST bisect one another. (2) (2) (9) (Total 13 marks)

Answer

4.4 (219 Votes)
Verificación de expertos
Aaron Professional · Tutor for 6 years

Answer

(a) (b) (c) The lines and bisect each other.

Explanation

## Step1: First, we need to find the vectors and . Since the points and divide and in the ratio 1:4 respectively, we can use the formula for dividing a line segment in a given ratio to find these vectors. The formula is and .## Step2:Substitute and into the formulas from Step1 to get and .## Step3:To find , we subtract from . This gives .### ## Step4:Next, we find the vectors and using the same method as in Step1. We get and .## Step5:Since and , we substitute these into the formulas from Step4 to get and .## Step6:To find , we subtract from . This gives .### ## Step7:Finally, we can see that , which means that the lines and bisect each other.