A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution. What is the molarity of this solution? A 1.3 mathrm(M) B 0.44 mathrm(M) C 0.25 mathrm(M)

Question

A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution. What is the molarity of this solution? A 1.3 mathrm(M) B 0.44 mathrm(M) C 0.25 mathrm(M)

Answer 1

The molarity of the solution is C) 0.25M.

Answer 2

## Step 1Molarity (M) is defined as the number of moles of a substance per liter of solution. It can be calculated using the formula:### **M = \frac{mol}{L}**## Step 2To find the molarity of the KOH solution, we first need to find the number of moles of KOH. The molar mass of KOH (where K=39.1, O=16, H=1) is approximately 56.1 g/mol.## Step 3The number of moles is calculated by dividing the mass of the substance by its molar mass.### **Number of mol = \frac{mass(g)}{molar mass(g/mol)} = \frac{42.1g}{56.1g/mol} = 0.75 mol**## Step 4Since the solution is prepared to a total volume of 3.0 L, we can now calculate the molarity.### **M = \frac{mol}{L} = \frac{0.75 mol}{3 L} = 0.25 mol/L**Therefore, the correct answer is C) 0.25M.

Question

A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution. What is the molarity of this solution? A 1.3 mathrm(M) B 0.44 mathrm(M) C 0.25 mathrm(M)

Answer

Answer

Explanation