Question
(29. The diagram shows three cups A, B and C. square (a) (i) The mass of water in each cup is 200 g. Calculate the energy, in joules, transferred from the water in a cup when the temperature of the water falls by 8^circ C Specific heat capacity of water=4200J/kg^circ C __ Energy transferred = __ J
Answer
4
(228 Votes)
Gideon
Master · Tutor for 5 years
Answer
### The energy transferred is approximately 6720 Joules.
Explanation
## Step1: Understanding the problem### The problem is asking to find the energy transferred from the water in a cup when the temperature of the water falls by 8°C. We know that the mass of the water in each cup is 200g and the specific heat capacity of water is 4200 J/kg°C. We can use the formula for calculating heat energy, Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.## Step2: Converting the mass to kilograms### Since the specific heat capacity is given in J/kg°C and the mass is given in grams, we need to convert the mass from grams to kilograms. 1 kilogram is equal to 1000 grams, so 200 grams is equal to 0.2 kilograms.## Step3: Substituting the values into the formula### Now we can substitute the values into the formula. The mass m is 0.2 kg, the specific heat capacity c is 4200 J/kg°C, and the change in temperature ΔT is 8°C. So, Q = (0.2 kg) * (4200 J/kg°C) * (8°C).## Step4: Calculating the energy transferred### By multiplying these values together, we can find the energy transferred from the water in the cup.