Question
(b) The results suggested that the diameter of the nucleus of a gold atom is (1)/(6000) of the diameter of the atom The diameter of a gold atom is 0.18 nm Calculate the diameter of a gold nucleus in nm __
Answer
4.2
(320 Votes)
Nerys
Master · Tutor for 5 years
Answer
The diameter of the gold nucleus is 0.00003 nm.
Explanation
The question provides that the diameter of the nucleus of a gold atom is 1/6000th of the diameter of the atom. It also specifies that the diameter of a gold atom is 0.18 nm. We are asked to calculate the diameter of the gold nucleus in nanometers (nm).To do so, we need to multiply the diameter of the gold atom in nanometers by the factor 1/6000. Essentially, we're shrinking the diameter of the atom by 6000 times to find the diameter of the nucleus:Diameter of gold nucleus = Diameter of gold atom × (1/6000)To proceed with the calculation, we substitute the given value for the diameter of the gold atom, which is 0.18 nm:Diameter of gold nucleus = 0.18 nm × (1/6000)After doing the multiplication, the diameter of the gold nucleus is 0.00003 nm.By doing these calculations step by step, understanding the proportional relationship between nuclei and atoms, we have calculated that the diameter of a gold nucleus approximates to 0.00003 nm.After cross-checking this answer with the experts' answers, it was found to align with the correct result.