Question
1. What is the temperature change of a 130 g plece of aluminum whose specific heat is 2.89J/gcdot ^circ C after 1000 J of heat energy is applied? 2. How much energy is required to heat 22.5g of water from 34^circ C to 45^circ C 3. What is the specific heat of water if a beaker containing water weighs 150.0 g and is heated with a 16000 J of heat energy?The temperature of water changed from 22.0^circ C to 23.0^circ C 4. What is the mass of the beaker containing water if the temperature of water is 100^circ C and the specific heat of water is 4.18J/gOC after 1800J of heat energy is applied?
Answer
4.3
(247 Votes)
Jena
Professional · Tutor for 6 years
Answer
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Explanation
## Step1: Identify the formula for temperature change The formula for calculating temperature change is
, where:-
is the heat energy added (in Joules),-
is the mass of the substance (in grams),-
is the specific heat capacity (in
),-
is the change in temperature (in
).We need to reorganize this to solve for
:
## Step2: Calculate temperature change for aluminum Given:- Mass
g- Specific heat capacity
J/g·°C- Heat energy
JUsing the formula:
## Step3: Determine energy required to heat water Given:- Mass
g- Initial temperature
- Final temperature
- Specific heat capacity
J/g·°C (standard value for water)Calculate temperature change first:
Using the formula
:
## Step4: Calculate the specific heat of water Given:- Mass of water
g- Heat energy
J- Temperature change
Using the rearranged specific heat formula
:
## Step5: Calculate the mass of the beaker containing water Given:- Temperature change
- Specific heat
- Heat energy
Using the formula rearranged for mass
: