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1. what is the temperature change of a 130 g plece of aluminum whose specific heat is 2.89j/gcdot ^circ c after 1000 j of heat energy

Question

1. What is the temperature change of a 130 g plece of aluminum whose specific heat is 2.89J/gcdot ^circ C after 1000 J of heat energy is applied? 2. How much energy is required to heat 22.5g of water from 34^circ C to 45^circ C 3. What is the specific heat of water if a beaker containing water weighs 150.0 g and is heated with a 16000 J of heat energy?The temperature of water changed from 22.0^circ C to 23.0^circ C 4. What is the mass of the beaker containing water if the temperature of water is 100^circ C and the specific heat of water is 4.18J/gOC after 1800J of heat energy is applied?

Answer

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Answer

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Explanation

## Step1: Identify the formula for temperature change The formula for calculating temperature change is , where:- is the heat energy added (in Joules),- is the mass of the substance (in grams),- is the specific heat capacity (in ),- is the change in temperature (in ).We need to reorganize this to solve for : ## Step2: Calculate temperature change for aluminum Given:- Mass g- Specific heat capacity J/g·°C- Heat energy JUsing the formula: ## Step3: Determine energy required to heat water Given:- Mass g- Initial temperature - Final temperature - Specific heat capacity J/g·°C (standard value for water)Calculate temperature change first: Using the formula : ## Step4: Calculate the specific heat of water Given:- Mass of water g- Heat energy J- Temperature change Using the rearranged specific heat formula : ## Step5: Calculate the mass of the beaker containing water Given:- Temperature change - Specific heat - Heat energy Using the formula rearranged for mass :