Question
A soccer player kicks a 0.5 kg ball,and it travels at a of velocity of 8m/s. If the player's foot was in contact with the ball for 0.3 seconds, what force was the ball kicked with? a 12N b b 4.8 N C 10.4 N d 13.33 N
Answer
4.7
(291 Votes)
Rhiannon
Veteran · Tutor for 11 years
Answer
d
Explanation
To find the force with which the soccer player kicked the ball, we can use the impulse-momentum theorem, which states that the impulse on an object is equal to the change in its momentum. Impulse can also be calculated as the force applied multiplied by the time for which it was applied (Impulse = Force × Time). The change in momentum is equal to the mass of the ball multiplied by the change in velocity (since the initial velocity was 0 m/s).Given:- Mass of the ball (m) = 0.5 kg- Final velocity of the ball (v) = 8 m/s- Time of contact (t) = 0.3 sWe assume the initial velocity (u) is 0 m/s because the ball was initially at rest. The change in velocity (∆v) is then equal to the final velocity minus the initial velocity, which is 8 m/s - 0 m/s = 8 m/s.The change in momentum (∆p) is mass times the change in velocity:∆p = m × ∆v = 0.5 kg × 8 m/s = 4 kg·m/sNow, using the impulse-momentum theorem:Impulse = Change in momentum = Force × TimeWe can rearrange this to solve for the force (F):F = Impulse / Time = ∆p / t = 4 kg·m/s / 0.3 s = 13.33 NTherefore, the force with which the ball was kicked is 13.33 N.