Question
The table shows the relative atomic masses of some common elements. Use this information to work out the relative formula mass of the compound with the formula shown below the table. Enter a number Element & Relative atomic mass hydrogen & 1 carbon & 12 nitrogen & 14 oxygen & 16 sodium & 23 magnesium & 24 phosphorus & 31 sulfur & 32 chlorine & 35.5 calcium & 40 iron & 56 [ mathrm(Fe)_(2)(mathrm(SO)_(4))_(3) ]
Answer
4.5
(227 Votes)
Glenna
Master Β· Tutor for 5 years
Answer
(2*56) + (3*32) + (12*16) = 400.
Explanation
The formula πΉπβ(ππβ)β represents Iron(III) sulfate. The relative formula mass (Mπ) of a compound is the sum of the relative atomic masses, Ar, of the atoms in its formula. Here, we need to sum of the atomic masses of 2 Iron (Fe) atoms, 3 atoms of Sulfur (S), and 12 Oxygen (O) atoms (since there are 3 sulfate ions each containing 4 oxygen atoms).From the information given in the question, we know that the relative atomic mass of:- Iron (Fe) is 56 - Sulfur (S) is 32- Oxygen (O) is 16So we can work out the relative formula mass of Iron(III) Sulfate ([Feβ(SOβ)β) as follows:Mass of 2 Iron atoms + Mass of 3 Sulfur atoms + Mass of 12 Oxygen atoms: