Question
Q7 A student investigated the reactions of copper carbonate and copper oxide with dilute hydrochloric acid. In both reactions one of the products is copper chloride. (a) A student wanted to make 11.0 g of copper chloride. The equation for the reaction is: CuCO_(3)+2HClarrow CuCl_(2)+H_(2)O+CO_(2) Relative atomic masses. A: H=1;C=12;O=16;Cl=35.5;Cu=63.5 Calculate the mass of copper carbonate the student should react with dilute hydrochloric acid to make 11.0 g of copper chloride. __ Mass of copper carbonate=
Answer
4.3
(195 Votes)
Gerald
Professional · Tutor for 6 years
Answer
By applying the steps outlined above:Step 1: Molar mass of CuCl2 = 134.5 g/mol, Molar mass of CuCO3 = 123.5 g/molStep 2: Moles of CuCl2:
(approximately)Step 3: Moles of CuCO3 = 0.0818. Step 4: Mass of CuCO3 = Molar mass of CuCO3 (123.5 g/mol) × Moles of CuCO3 (0.0818) = 10.0717 g Therefore, the student should react approximately
of copper carbonate. We typically report to appropriate significant figures. Since tone tenth place was given for 11.0 g of CUCL2 , we guide the student to use approximately 10.1 g of copper carbonate for reaction with the hydrochloric acid.
Explanation
## Step 1: Determine the molar mass of the compoundsUsing the provided relative atomic masses, we first determine the molar mass of the compounds involved in the reaction. For copper chloride (CuCl2), we use \(1 \times 63.5 (for~Cu) + 2 \times 35.5 (for~Cl) = 134.5 \,g/ mol \). Similarly, for Copper Carbonate (CuCO3), the molar mass will be \(63.5 (for Cu) + 12 (for C) + 3 \times 16 (for three O's) = 123.5 g/ mol\).## Step 2: Calculate the amount of CuCl2 in molesNext, we use the mass of CuCl2 (which is already given as 11.0 g) and divide it by its molar mass to find how many moles of CuCl2 are being made. So, \(11.0\, g/ (134.5\, g/mol)\). ## Step 3: Apply stoichiometry From the balance chemical equation we can see that 1 mole of CuCO3 produces 1 mole of CuCl2. Hence, the number of moles of CuCO3 required will be the same as the moles of CuCl2. ## Step 4: Find the massKnowing the moles of CuCo3 and its molar mass, we multiply the moles of CuCO3 by its molar mass to find its mass. #