Question
1. HaǐTH lim _(xarrow -infty )(1+(2)/(x))^x+5
Answer
4.3
(125 Votes)
Sali
Elite · Tutor for 8 years
Answer
\(\lim_{x \to -\infty}(1+\frac{2}{x})^x + 5 = \frac{1}{e^2} + 5\)
Explanation
The given problem is to find the limit as
approaches negative infinity of the expression \((1+\frac{2}{x})^x + 5\). This is a classic limit problem involving an exponential expression.To solve this, we need to recognize that as
approaches negative infinity,
approaches 0. Therefore, the base
of the exponential expression approaches 1.The expression \((1 + \frac{2}{x})^x\) can be compared to the well-known limit \(\lim_{x \to \infty}(1 + \frac{1}{x})^x\), which is the definition of
, the base of natural logarithms. However, in our case, since
approaches negative infinity, the expression \((1 + \frac{2}{x})^x\) approaches
because the exponent is negative, which flips the base of the exponential expression.Finally, we add 5 to this limit, as indicated in the original expression, to get the final result.