[ 2 mathrm(H)_(2) mathrm(~S)(g) leftharpoons 2 mathrm(H)_(2)(g)+mathrm(S)_(2)(g) ] A rigid reaction vessel contains mathrm(H)_(2) mathrm(~S)(g) in equilibrium with mathrm(H)_(2)(g) and mathrm(S)_(2)(g) at 1200 mathrm(~K) , as represented by the equation above. The partial pressures of the gases at equilibrium arif shown in the table below. Gas & }(c) Equilibrium partial pressure (atm) mathrm(H)_(2) mathrm(~S) & 1.2 mathrm(H)_(2) & 0.21 mathrm(~S)_(2) & 0.016 Calculate the value of the equilibrium constant, K_(p) , for the reaction at 1200 mathrm(~K) .

#ExplanationThe equilibrium constant, , is a measure of the ratio of the concentrations of the products to the reactants at equilibrium, each raised to the power of their stoichiometric coefficients in the balanced chemical equation. For the given reaction, the equilibrium constant is given by: where [H_2S], [H_2], and [S_2] represent the equilibrium partial pressures of , , and respectively.Given the equilibrium partial pressures of the gases: we can substitute these values into the equation for to calculate its value.#AnswerSubstituting the given values into the equation for , we get: Calculating the above expression, we find that is approximately 0.000588.