What would be the force exerted on a conductor 60 cm long carrying a current of 10 A, when placed at right angles to a magnetic field of flux density 3? a 1.8 ml. b 18 N C 36 N d 54 N

## Step 1: Import the formula**The force exerted on a straight conductor by a magnetic field can be calculated using the formula**: ### ** *** is the force,* is the current in the wire,* is the length of the wire,* is the magnetic field strength,* is the angle between the direction of the current and the direction of the magnetic field.## Step 2: Understand specifics of the questionAccording to this question, this conductor is at right angles to the magnetic field, meaning the angle ( ) between the conductor and the field is 90 degrees. From trigonometry, we know that degrees equals to 1.## Step 3: Capture provided details.The question provides the following important details:* The length of the conductor ( ) is 60 cm. But we want this to be in meters, because the standard unit of length in physics questions involving magnetic force is meter. So, \( L = 60 \times \left(\frac{1 m}{100 cm}\right) = 0.6 \) m.* The current it carries ( ) is 10 A.* The strength of the magnetic field ( ) is 3 T.## Step 4: Substitute details into the formula.We can now replace all the values provided in the question into the formula and we have:### ** **## Step 5: Analysis Calculations to solve the problem.Pluging these values into the formula: 10 A, 0.6 m, and 3 T , a force of 18 N is obtained.