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21 the time period , t seconds, of a simple pendulum of length 7cm is given by the formula t=2pi sqrt ((l)/(g)) katie uses a simple

Question

21 The time period , T seconds, of a simple pendulum of length 7cm is given by the formula T=2pi sqrt ((l)/(g)) Katie uses a simple pendulum in an experiment to find an estimate for the value of g. Here are her results. l=52.0 correct to 3 significant figures. T=1.45 correct to 3 significant figures. Work out the upper bound and the lower bound for the value of g. Use pi =3.142 You must show all your working.

Answer

4.7 (184 Votes)
Verificación de expertos
Cecilia Master · Tutor for 5 years

Answer

The upper bound for the value of is approximately and the lower bound for the value of is approximately .

Explanation

## Step 1:### The formula for the period of a simple pendulum is given by , where is the length of the pendulum and is the acceleration due to gravity.## Step 2:### To find , we rearrange the equation to solve for . Squaring both sides, we get: ### Simplifying, we obtain: ### Rearranging to solve for , we get: ## Step 3:### Given cm and seconds, we first find the upper and lower bounds for and .### For :#### The upper bound is cm.#### The lower bound is cm.### For :#### The upper bound is seconds.#### The lower bound is seconds.## Step 4:### Calculate the upper bound for using the lower bound of and the upper bound of : ## Step 5:### Calculate the lower bound for using the upper bound of and the lower bound of : ## Step 6:### Perform the calculations: