Question
The specific heat of water is 4.18J/gcdot ^circ C How much heat does 225.0 g of water release when it cools from 85.5^circ C to 50.0^circ C Use the formula q=mC,Delta T. 3.26times 10^4J 3.34times 10^4J 1.27times 10^5J 2.90times 10^5J
Answer
4.2
(261 Votes)
Xavier
Professional · Tutor for 6 years
Answer
Sure, let's work through the problem step by step.Question:How much heat does
of water release when it cools from
to
?Given formula:
Step 1:Identify the values given in the problem:- Mass (
):
- Specific heat of water (
):
- Initial temperature (
):
- Final temperature (
):
Step 2:Calculate the temperature change (
):
Step 3:Now, substitute the values into the formula:
Step 4:Calculate the heat (
):
Step 5:Solve for
and substitute the values:
Now, calculate the value of
.Step 6:Take a deep breath and perform the calculation to get the final answer.
So, the correct answer is
.**Answer:**
DONE