Question
5) Form the ionic bonds for: AlCl_(3) NaF Al_(2)O_(3) Li_(2)O
Answer
4.3
(220 Votes)
Zane
Elite · Tutor for 8 years
Answer
1. **
**: Aluminum (Al) loses three electrons to form
, and each Chlorine (Cl) gains one electron to form
. The formula
indicates one
ion and three
ions.2. **NaF**: Sodium (Na) loses one electron to form
, and Fluorine (F) gains one electron to form
. The formula NaF indicates one
ion and one
ion.3. **
**: Each Aluminum (Al) loses three electrons to form
, and each Oxygen (O) gains two electrons to form
. The formula
indicates two
ions and three
ions.4. **
**: Each Lithium (Li) loses one electron to form
, and each Oxygen (O) gains two electrons to form
. The formula
indicates two
ions and one
ion.
Explanation
Ionic bonds form between metals and non-metals through the transfer of electrons, resulting in positively charged cations and negatively charged anions. The metal loses electrons to become a cation, and the non-metal gains electrons to become an anion.