Identify the missing particle in the following nuclear reaction: (}^99_{43)Tcarrow ldots +^0-1^0 A. (}^99_{43)Es 7 B. (}^99_{43)Tc 7 C. ? (}^99_{42)Mo D. (}_{44)Ru 7

Answer:# Explanation: ## Step 1 This problem involves a nuclear reaction, specifically a type of nuclear reaction known as beta decay. In beta decay, a neutron in the nucleus of an atom transforms into a proton. This process releases an electron (also known as beta minus, or ) and an antineutrino. The electron has a charge of -1 and no mass number, which is represented as in the given equation.## Step 2 When a neutron transforms into a proton during beta decay, the atomic number (Z) of the atom increases by 1 because the number of protons in the nucleus increases by 1. However, the mass number (A) of the atom remains the same, since the atom does not lose or gain any nuclear particles overall during the process.## Step 3 The electron that is emitted during beta decay is represented in the given equation as . This indicates that a technetium atom ( ) has undergone beta decay, emitting an electron.## Step 4 Looking at the options provided, we can see that option D ( ) is the correct choice. This is because its atomic number has increased by 1 (from 43 to 44), while the mass number remains the same (99), which is consistent with the characteristics of beta decay.## Step 5 Options A, B, and C do not match these characteristics, so they are not correct.# Answer: 'D. '