5) "Viral" Video. You hear about a super-funny video that's been posted on YouTube. When you go to view it you see that 1,345 ,397 people have viewed it since it was posted 3 days and 10 hours ago. The increase in the number of viewings follows the law of uninhibited growth with k=0.1721 when time is measured in hours yassume a starting value of 1 viewing). 4) How many people had viewed this video after it had been posted 2 hours? 2 days? b) When did the number of times viewed exceed 1 million?

## Step 1: Understanding the problemThe problem is about the law of uninhibited growth, which is a type of exponential growth. The general formula for this type of growth is \(N(t) = N_0 \cdot e^{kt}\), where \(N(t)\) is the final amount, is the initial amount, is the growth rate, and is the time.In this case, the initial amount is 1 (the starting view), the growth rate is 0.1721, and the time is in hours.## Step 2: Calculating the number of views after 2 hours and 2 daysTo find the number of views after 2 hours and 2 days, we substitute the respective values of into the formula.### For 2 hours:\(N(2) = 1 \cdot e^{0.1721 \cdot 2}\)### For 2 days (48 hours):\(N(48) = 1 \cdot e^{0.1721 \cdot 48}\)## Step 3: Calculating when the views exceeded 1 millionTo find out when the views exceeded 1 million, we set \(N(t) = 1000000\) and solve for .###