Which of the following is the best representation of the balanced net ionic equation for the aqueous reaction below? Zr(OH)_(4)(s)+4HNO_(3)(aq)arrow Zr(NO_(3))_(4)(aq)+4H_(2)O(l) Zr(OH)_(4)(s)+4H^+(aq)arrow Zr^4+(aq)+4H_(2)O(l) Zr(OH)_(4)(s)+4HNO_(3)(aq)arrow Zr(NO_(3))_(4)(aq)+4H_(2)O(l) Zr(OH)_(4)(s)+4H^+(aq)+4NO_(3)^-(aq)arrow Zr^4+(aq)+4NO_(3)^-(aq)+4H_(2)O(l) Zr(OH)_(4)(s)+4NO_(3)^-(aq)arrow Zr^4+(aq)+4NO_(3)^-(aq)

Let's tackle this problem step by step.Step 1: Write down the full chemical equation.The full chemical equation given is: Step 2: Identify the states of the reactants and products.Zirconium hydroxide (\(\mathrm{Zr(OH)_4}\)) is a solid, nitric acid ( ) is in aqueous solution, zirconium nitrate (\(\mathrm{Zr(NO_3)_4}\)) is in aqueous solution, and water ( ) is a liquid.Step 3: Write the net ionic equation.To write the net ionic equation, we need to focus on the species that actually change during the reaction. In this case, \(\mathrm{Zr(OH)_4}\) is reacting with the hydrogen ions ( ) from the nitric acid to form zirconium ions ( ) and water. The nitrate ions ( ) are spectator ions and do not participate in the reaction.Step 4: Balance the net ionic equation.The balanced net ionic equation should reflect the stoichiometry of the reactants and products that are actually involved in the reaction. The solid zirconium hydroxide reacts with hydrogen ions to form zirconium ions and water. The balanced net ionic equation is: Step 5: Confirm the answer.Looking at the options provided, the first one matches our balanced net ionic equation: **Highlight the accurate answer:**The best representation of the balanced net ionic equation for the given reaction is: