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whilig and balancing chlemical equations pre-test the chemical equation for the formation of ammonia is unbalanced.

Question

whilig and Balancing Chlemical equations Pre-Test The chemical equation for the formation of ammonia is unbalanced. 3H_(2)(g)+N_(2)(g)arrow NH_(3)(g) If three molecules of hydrogen react with one molecule of nitrogen, how many molecules of ammonia would be formed? 1 2 () 3 4 Active 6 TIME 51:58

Answer

4.7 (175 Votes)
Verificación de expertos
Yves Professional · Tutor for 6 years

Answer

### 2

Explanation

## Step 1: Identify the stoichiometry of the reactants and products### The unbalanced chemical equation is \(3 \mathrm{H}_{2}(\mathrm{~g}) + \mathrm{N}_{2}(\mathrm{~g}) \rightarrow \mathrm{NH}_{3}(\mathrm{~g})\). This indicates that 3 molecules of hydrogen react with 1 molecule of nitrogen.## Step 2: Balance the chemical equation### For the chemical equation to be balanced, the number of atoms of each element must be the same on both sides. The balanced equation is \(3 \mathrm{H}_{2}(\mathrm{~g}) + \mathrm{N}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g})\).## Step 3: Determine the ratio of reactants to products### From the balanced equation, 3 molecules of hydrogen and 1 molecule of nitrogen produce 2 molecules of ammonia.#