/hich of the following numerical expressions gives the number of particles in 2.0 g of Ne? A (6.0times 10^23 particles /mol)/(2.0g) B (6.0times 10^23 particles /mol)/(20.18g/mol) C (2.0g)/(20,18g/mol)(6.0times 10^23 particles /mol) D (20.18g/mol)/(2.0g)(6.0times 10^23particles/mol)

The task here is to find the number of particles (in this case atoms, as we're dealing with a monoatomic gas - Neon) in 2.0 g of Neon. To do this, we need to convert the amount from grams to moles and then to atoms.In each mole of any substance, be it atoms, molecules, electrons etc., there are approximately Avogadro's Number (~ ) of those particles. This is essential for counting particles at the atomic and molecular scale.Neon has an atomic mass of approximately 20.18 grams per mole. Knowing this, we can then address how to correctly convert from grams to moles and consequently to particle count.Option (A) simply divides Avogadro's number by the given mass. This is incorrect, as in a ratio of 'Particles to Moles' (Avogadro's number), there isn't a direct link to the deposited mass of the element. The atomic/molar mass must be included in the calculation. Option (B) effectively divides the available mass of Neon (2 g) by its molar mass (20.18 g/mol), converting grams to moles. However, Avogadro's number is divided by the molar mass - which is not directly linked to the particle count on its own, making this option incorrect.Option (D) also incorrectly frames how the molar mass/Avogadro's Number are used in this conversion, complicating the logic of how 'g' converts to 'mol' and then onto the particle count.But, in Option (C), the front ratio (2.0g / 20.18 g/mol) properly accounts for mass to molar conversion, providing the correct number of moles. The back term (Avogadro's Number per mol) hits the last conversion - from moles to particle count. As the '/' conventions divide down, everything constructs to provide an answer in the correct unit: atoms.