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a measuring cylinder contains 50cm^3 of water. a ball is submerged in the measuring cylinder, and the water level now reads 78cm^3 the

Question

A measuring cylinder contains 50cm^3 of water. A ball is submerged in the measuring cylinder, and the water level now reads 78cm^3 The ball has a mass of 33 g. Calculate the density of the ball, giving your answer to 2 significant figures. Enter number g/cm^3

Answer

4 (138 Votes)
Verificación de expertos
Walter Elite · Tutor for 8 years

Answer

The density of the ball is .

Explanation

## Step 1:Determine the volume of the ball. The volume of the ball is equal to the volume of the water displaced by the ball. This can be calculated by subtracting the initial volume of water from the total volume with the ball submerged.### **Volume of ball = Total volume with ball - Initial volume of water**## Step 2:Calculate the volume of the ball.### **Volume = 78 \mathrm{~cm}^{3} - 50 \mathrm{~cm}^{3} = 28 \mathrm{~cm}^{3}**## Step 3:Convert the mass of the ball from grams to kilograms if necessary. However, since the final answer is required in , we can keep the mass in grams.### **Mass = 33 \mathrm{~g}**## Step 4:Calculate the density of the ball. The density equals the mass divided by the volume (in grams per cubic centimeter, or ).### **Density = \frac{\text{Mass}}{\text{Volume}}**## Step 5:Perform the calculation to find the density.### **Density = \frac{33 \mathrm{~g}}{28 \mathrm{~cm}^{3}} \approx 1.18 \mathrm{~g} / \mathrm{cm}^{3}**## Step 6:Round the answer to 2 significant figures.### **Density \approx 1.2 \mathrm{~g} / \mathrm{cm}^{3}**