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a propane tank containing 55l has 2.46 moles of the gas . ( c_(3)h_(8) is propane what would be the of moles if 1/2 of the gas is used?

Question

A propane tank containing 55L has 2.46 moles of the gas . ( C_(3)H_(8) is propane What would be the of moles if 1/2 of the gas is used?

Answer

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Answer

The number of moles in the tank after 1/2 of the propane gas is used would be 1.23 moles.

Explanation

This problem can be solved using the inverse association or relationship between mole and volume of propane gas (C3H8).We start by realizing that in these kinds of questions, the initial number of moles, initial volume, the resulting volume after using the gas and the number of resulting moles all have a direct relationship. Basically, it implies that if the volume utilized is decreased by half, the number of moles will also reduce by the same fraction/percentage geometrically. Hence, if 1/2 of the volume of the propane is used, it means its mean 55L/2 which equals to 27.5L volume would remain.Originally, the tank has 2.46 moles of propane gas and if half is used (as stated by the question), the corresponding moles left would also halved (this is the direct relationship between mole and volume of the gas).Hence, the present moles of the remains volume after usage would be 2.46/2 = 1.23 moles.