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0 2. 3 calculate the percentage by mass of oxygen in lithium sulfate (li_(2)so_(4)) relative atomic mass (a_(c)): o=16 relative formula

Question

0 2. 3 Calculate the percentage by mass of oxygen in lithium sulfate (Li_(2)SO_(4)) Relative atomic mass (A_(c)): O=16 Relative formula mass (M_(1)):Li_(2)SO_(4)=110 Give your answer to 2 significant figures. __ [4 marks] by mass of oxygen (2 significant figures)= 0 2].4 A solution of lithium sulfate contains 0.30 g of lithium sulfate in 25cm^3 4 Calculate the concentration of lithium sulfate in g/dm^3 __ [3 marks] Concentration=g/dm^3

Answer

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Answer

The percentage by mass of oxygen in lithium sulfate is approximately (rounded to 2 significant figures).The concentration of lithium sulfate in the solution is .

Explanation

## Step 1: Calculate the percentage by mass of oxygen in lithium sulfateLithium sulfate ( ) consists of 2 lithium atoms, 1 sulfur atom, and 4 oxygen atoms. The atomic mass of oxygen is given as 16. The relative formula mass of lithium sulfate is given as 110. ### The formula to calculate the percentage by mass of oxygen is: ### Substituting the given values into the formula, we get:### ## Step 2: Calculate the concentration of lithium sulfate in A solution of lithium sulfate contains 0.30 g of lithium sulfate in 25 cm³. ### The formula to calculate the concentration is: ### Note that the volume of the solution needs to be converted from cm³ to dm³. 1 dm³ = 1000 cm³. So, 25 cm³ = 0.025 dm³.Substituting the given values into the formula, we get:###