An arrow on a spinner is spun 250 times. Some of the results are shown below. Number shown & 1 & 2 & 3 & 4 & 5 Frequency & 25 & 53 & 62 & & The relative frequency of landing on a 4 is the same as the relativ frequency of landing on a 5 Work out the relative frequency of landing on a 4

## Step 1: Understanding the ProblemGiven in the problem that the arrow was spun 250 times and some of the frequencies (events) are given for the numbers the spinner landed on. We know that number 4 and 5 have the relative frequency, but we don't know their individual frequencies.## Step2: Deduce the Accumulated Frequency or Outcomes for 4 + 5Since the arrow was spun 250 times, whatever the accumulated outcome for the copper spun on 4 & 5 should sum up with the already known outcomes for 1, 2, and 3 which sum = (25+53+62=140).### ## Step3: Divide the Remaining Number As the question implies, spinner number 4 and 5 have the same relative frequency, so we should divide the 110 outcomes by 2 or can we written as .## Step4: Calculate for the Relative Frequency Relative frequency is the fraction of times a spinner lands on specific numbers (events). In this case, we have total spins as 250 and, for numbers 4 and 5 as same 55 spins. The relative frequency will be in more simple form as