Home
/
Physics
/
(b)the pressure of the helium in the balloon is 100000 pa. the volume of the balloon is 0.030m^3 the balloon is compressed at a

Question

(b)The pressure of the helium in the balloon is 100000 Pa. The volume of the balloon is 0.030m^3 The balloon is compressed at a constant temperature causing the volume to decrease to 0.025m^3 No helium leaves the balloon. Calculate the new pressure in the balloon. __ New pressure= (2)

Answer

3.7 (207 Votes)
Verificación de expertos
Orson Elite · Tutor for 8 years

Answer

[120000 Pa]

Explanation

## Step1: Recognize the problem typeThe problem describes a change in the volume of a gas - helium in a balloon - that happens under constant temperature, with no gas entering or leaving the system. This is a case of Boyle's law in action, represented as , wherein and denote initial pressure and volume, while and indicate final pressure and volume respectively.## Step2: Substitute given values into the formulaWe are given the following variables: Pa, , and .To calculate the unknown , we insert these variables into Boyle's law and solve for .### **The formula is given as:** ### Insert the variables into the equation:\( P_2= \frac {(100000 \mathrm{~Pa})*(0.030 \mathrm{~m}^{3})}{0.025 \mathrm{~m}^{3}} \)## Step3: Solve step-wise and verify Do the calculation carefully. Multiply with to get .### Then divide with to get: .