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4. In Humans, Having Freckles (F) Is Dominant over Not Having Freckles (f). A Man Who Is Homozygous and Has Freckles Marries a Woman

Question

4. In humans, having freckles (F) is dominant over not having freckles (f). A man who is homozygous and has freckles marries a woman who is heterozygous. Fill in the information below to determine the probability of their offspring having freckles! Father's genotype F F Mother's genotype Probability of each genotype in the offspring: mathrm(FF)=50 % mathrm(FF)=50 % mathrm(ff)=0 % Probability of each phenotype in the offspring: Freckles = No Freckles =

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4.2 (197 Votes)
Verificación de expertos
Vaughn Elite · Tutor for 8 years

Answer

Mother's genotype: FfProbability of each genotype in the offspring:FF = 50%Ff = 50%ff = 0%Probability of each phenotype in the offspring:Freckles = 100%No Freckles = 0%

Explanation

## Step 1In this problem, we are dealing with the principles of genetics, specifically the concept of dominance. Dominance is a relationship between alleles of a gene in which one allele masks the expression of another allele in the organism's phenotype. In this case, the dominant trait is having freckles (represented by the letter 'F'), while the recessive trait is not having freckles (represented by the letter 'f').## Step 2The man in this scenario is homozygous for the freckle trait, which means he has two copies of the same allele. Therefore, his genotype is 'FF'.## Step 3The woman is heterozygous for the freckle trait, which means she has two different alleles of a gene. Therefore, her genotype is 'Ff'.## Step 4When these two individuals mate, their genetic traits are inherited by their offspring. We can use a Punnett square to determine the possible genotypes of their offspring.## Step 5The Punnett square for this cross would look like this:| | F | F ||-------|-------|-------|| F | FF | FF || f | Ff | Ff |## Step 6From the Punnett square, we can see that each offspring has a 50% chance of being 'FF' and a 50% chance of being 'Ff'.## Step 7According to the principles of dominance, both 'FF' and 'Ff' will display freckles. Therefore, the probability of an offspring having freckles is 100%, and the probability of an offspring not having freckles is 0%.