Round to 2 decimal places when needed. The velocity of an object dropped from a height of his given by the function V= sqrt (2gh) where gi is the gravitational constant, 32.2ft/s^2 . If an object is dropped from the roof of a building that is 1000 it tall, how fast is it traveling when it hits the ground?

## Step 1:We are given the formula for the velocity of an object dropped from a height , which is , where is the gravitational constant and is the height from which the object is dropped.## Step 2:We are given that ft and ft/s². We need to substitute these values into the formula to find the velocity when the object hits the ground.## Step 3:Substitute the given values into the formula, we get .## Step 4:Perform the multiplication and square root operations to find the value of .## Step 5:Round the calculated value to two decimal places as instructed in the question.