A recently discovered element, Moscovium (Mc), has 115 protons in the nucleus of one atom and has been placed in group 15, period 7 on the periodic table. Which THREE correctly predict the properties of Moscovium (Mc)? A. It will have less electronegativity than P. B. It will have less ionization energy than Te. C. It will have an atomic radius larger than Ba D. It will have an atomic radius larger than P_(0)

Question

A recently discovered element, Moscovium (Mc), has 115 protons in the nucleus of one atom and has been placed in group 15, period 7 on the periodic table. Which THREE correctly predict the properties of Moscovium (Mc)? A. It will have less electronegativity than P. B. It will have less ionization energy than Te. C. It will have an atomic radius larger than Ba D. It will have an atomic radius larger than P_(0)

Answer 1

A. It will have less electronegativity than P.B. It will have less ionization energy than Te.D. It will have an atomic radius larger than Po.

Answer 2

Moscovium (Mc), with 115 protons, is a heavy element in group 15 and period 7. Generally, elements in higher periods have larger atomic radii and lower electronegativity and ionization energy compared to elements in lower periods. Comparing Mc to other elements in different groups and periods helps predict its properties.

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