Question
This is an example of a __ bond. delta + delta - H-ddot (F): Nonpolar covalent bond Polar Covalent Bond ionic bond metallic bond
Answer
4.1
(227 Votes)
Cadi
Professional · Tutor for 6 years
Answer
To determine the type of bond present in a hydrogen fluoride (HF) molecule, we need to consider the electronegativity of the atoms involved and how the electrons are shared between them.Step 1: Identify the atoms in the molecule.The molecule in question is hydrogen fluoride, which consists of a hydrogen atom (H) and a fluorine atom (F).Step 2: Consider the electronegativity of the atoms.Electronegativity is a measure of how strongly an atom attracts electrons in a chemical bond. Hydrogen has an electronegativity of 2.1, while fluorine is the most electronegative element with an electronegativity of 3.98.Step 3: Determine the type of bond based on electronegativity difference.The difference in electronegativity between hydrogen and fluorine is 3.98 - 2.1 = 1.88. This significant difference indicates that the electrons in the bond are not shared equally. Fluorine, being more electronegative, will attract the bonding electrons more strongly than hydrogen.Step 4: Classify the bond type.- A nonpolar covalent bond occurs when the electronegativity difference between the two atoms is small (generally less than 0.5), and the electrons are shared relatively equally.- A polar covalent bond occurs when the electronegativity difference is significant (between 0.5 and 1.7), leading to an unequal sharing of electrons.- An ionic bond is typically formed when the electronegativity difference is greater than 1.7, and one atom donates electrons to the other, resulting in ions.- A metallic bond is a type of chemical bond found in metals where electrons are shared over many nuclei and electronic conduction occurs.Given the electronegativity difference of 1.88, the bond between hydrogen and fluorine is too polar to be considered nonpolar covalent but not quite extreme enough to be classified as ionic. Therefore, the bond in hydrogen fluoride is best described as a polar covalent bond.Answer: Polar Covalent Bond