- Cell Size Taking in Nutrients Three gel cubes similar to those from the previous screens have been placed in a colored solution that seeps into the gel much like nutrients enter a cell. Use the slider to see how the solution affected the gel cubes after some period of time. 2. How does this model support the conclusion that cells need to have a high amount of surface area relative to their total volume? Typeyouranswerhere disappointed

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- Cell Size Taking in Nutrients Three gel cubes similar to those from the previous screens have been placed in a colored solution that seeps into the gel much like nutrients enter a cell. Use the slider to see how the solution affected the gel cubes after some period of time. 2. How does this model support the conclusion that cells need to have a high amount of surface area relative to their total volume? Typeyouranswerhere disappointed

Answer 1

To answer this question, we need to understand the relationship between surface area, volume, and the rate at which substances can diffuse into a cell or, in this case, a gel cube.Step 1: Calculate the surface area and volume of the cube.Since the cube has an edge length of 1 cm, we can calculate its surface area and volume.- Surface area of a cube = 6 * (edge length)^2- Volume of a cube = (edge length)^3For a cube with an edge length of 1 cm:- Surface area = 6 * (1 cm)^2 = 6 cm^2- Volume = (1 cm)^3 = 1 cm^3Step 2: Understand the surface area to volume ratio.The surface area to volume ratio (SA:V) is crucial for the exchange of materials into and out of a cell (or gel cube in this case). A high SA:V ratio means that there is more surface area available for diffusion relative to the volume.For our cube:- SA:V ratio = Surface area / Volume = 6 cm^2 / 1 cm^3 = 6:1Step 3: Relate the SA:V ratio to nutrient uptake.A high SA:V ratio, as seen in smaller cells or gel cubes, means that there is more surface area available for the diffusion of nutrients and waste relative to the volume that needs to be serviced. This is beneficial because it allows for efficient exchange of materials. If a cell (or gel cube) is too large, the surface area is not sufficient to supply the interior volume with nutrients quickly enough, and waste removal becomes inefficient.Answer:This model supports the conclusion that cells need to have a high amount of surface area relative to their total volume because it demonstrates that with a higher SA:V ratio, diffusion of substances (like the colored solution) into the gel cube is more efficient. This is analogous to how cells take in nutrients and expel waste. Cells, therefore, tend to be small, or have structures that increase their surface area, to maintain a high SA:V ratio for effective exchange of materials with their environment.

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